How do you write the standard form of the equation of the parabola that has (-1/4, 3/2) vertex and (-2,0) point?

What is the equation in standard form of the parabola with a focus at (-18,30) and a directrix of y= 22?

How do you find the standard form of the equation of the parabola with a vertex of (1,0) and two points that are in the parabola are (5,3) and (5,-3)?

May 6, 2016 · In graphing #y=4 (x-3)^2 -2#, the vertex of the parabola is at what point?

The vertex is # (0,-2)#. Since #a>0#, the vertex is the minimum point, and the parabola will open upward.

Since focus lies below the vertex, The parabola is facing down. The vertex is at (h,k) Then the general form of the formula is - (x-h)^2=-4xxaxx (y-k) a is the distance between focus and vertex.

How do you graph the parabola #y=x^2-3x# using vertex, intercepts and additional points?

Knowing the intercepts and the vertex, and that it is a narrow, upside down parabola, should be enough to draw a graph, but remember that you can also easily calculate a few additional points on the …

Explanation: We know that the Standard Equation (eqn.) of the Parabola with Vertex at the Origin # (0,0)# and the Focus at # (0,b)# is,

Feb 23, 2016 · How do you write the equation of the parabola in vertex form given vertex (3, -3) point (0, 6)?